This is merely a subtype of Time n Work problems. and can be solved using our good ol’ STD table Method.

# Case 1: Women finish entire job

4 men and 6 women can complete a work in 8 days, while 3 men and 7 women can complete it in 10 days. In how many days will 10 women complete it?

Suppose 1 man can pour 1 bucketful of water in the tank in 1 minute.

If 6 men work together, they pour 6 buckets in a tank in 1 minute.

In short, you multiply the speed with number of person.

Our usual table

1 Man | 1 Woman | 4 men & 6 women | 3 men & 7 women | |

Speed | m | w | 4m+6w | 3m+7w |

Time | 8 | 10 | ||

distance |

Distance covered in each column is same.

So compare last two columns

Distance = distance

Speed x time = speed x time

(4m+6w)*8=(3m+7w)*10

Solve this equation and you get m=11w

Replace this value of w in last column

1 Man | 1 Woman | 4 men & 6 women | 3 men & 7 women | |

Speed | m | w | 4m+6w | 3(11w)+7w |

Time | 8 | 10 | ||

distance |

3(11w)+7w

=33w+7w

=40w

1 Man | 1 Woman | 4 men & 6 women | 3 men & 7 women | |

Speed | m | w | 4m+6w | 40w |

Time | 8 | 10 | ||

distance | 40w x 10= 400w |

So the total work is

Speed x time = distance

40w x 10= 400w

If 10 women work together, they’ve to cover 400w kms. Make a new column, run STD formula

1 Man | 1 Woman | 4 men & 6 women | 3 men & 7 women | 10 women | |

Speed | m | w | 4m+6w | 40w | 10w |

Time | 8 | 10 | ?? | ||

distance | 40w x 10= 400w | 400w |

10w x time =400w

Time =400w/ 10w=40days.

Answer: If 10 women work together, it’ll take 40 days to finish the job.

# Case 2: Women to finish remaining job

12 men can complete a piece of work in 4 days, while 15 women can complete the same work in 4 days. 6 men start working on the job and after working for 2 days, all of them stopped working. How many women should be put on the job to complete the remaining work, if it is to be completed in 3 days?

12 Man | 15 Woman | |

Speed | 12m | 15w |

Time | 4 | 4 |

distance |

Distance covered in both column is same so compare them

Speed x time = speed x time

12m x 4= 15w x 4

4m=5w

M=(5/4)w

The question is asking about number of women in the end, so better convert everything in terms of women.

**Given: ** 6 men start working on the job and after working for 2 days, all of them stopped working

Make a new column.

12 Man | 15 Woman | 6men | |

Speed | 12m | 15w | 6x (5/4)w |

Time | 4 | 4 | 2 |

distance | 60w | 6x (5/4)w x2=15w |

As you can see, I’ve applied STD formula in last two columns to find distance simultaneously.

Remaining work=60w minus 15w=45w

Required: we want to finish this work in 3 days.

**Asked:** *How many women should be put on the job to complete the remaining work, if it is to be completed in 3 days?*

Make a new column. Suppose we need “F” number of women so speed = f x w = Fw.

12 Man | 15 Woman | 6men | Find women | |

Speed | 12m | 15w | 6x (5/4)w | Fw |

Time | 4 | 4 | 2 | 3 |

Distance | 60w | 15w | 45w |

Time limit is given to us: complete remaining work in three days. So t=3 for last column.

Run STD on last column

Fw x 3 =45w

F=45w /3w

F=15

Answer : 15 women required.

**Important**: Remaining work is to be completed in 3 days. So t=3

If they had asked “total work is to be completed in 3 days”, we’ll need to take t=1, because those men already worked for 2 days to only 1 day left to complete the job (2+1=3 days)

# Case: Child labour

Twelve children take sixteen days to complete a work which can be completed by eight adults in twelve days. Sixteen adults started working and after three days ten adults left and four children joined them. How many days will they take to complete the remaining work?

12 kids | 8 men | |

Speed | 12k | 8m |

Time | 16 | 12 |

Distance |

Since work done in both columns is same

Speed x time = speed x time

12k x 16= 8m x 12

K=(1/2)m

Concentrate on middle column (8 men) run STD table on it. You get distance = 8m x 12 =96m

So total distance to be covered is 48m

Given: Sixteen adults started working and after three days ….

Means 16 men worked for 3 days.

12 kids | 8 men | 16 men | |

Speed | 12k | 8m | 16m |

Time | 16 | 12 | 3 |

Distance | 8m x 12=96m | 16m x 3=48m |

We’ve run STD on last column and got that 16 men covered 48m kms.

So remaining work is 96m minus 48m=48m

Given: after three days ten adults left and four children joined them

So now men left =16 minus 10 =6 men and 4 kids joins them so speed is 6m+4k

Make a new column

12 kids | 8 men | 16 men | Men & kids | |

Speed | 12k | 8m | 16m | 6m+4k |

Time | 16 | 12 | 3 | ?? |

Distance | 96m | 48m | 48m |

Run STD on last column

(6m+4k) x time =48m

But We already calculated that K=(1/2)m

Apply it in above equation{6m+4(1/2)m} x time =48m

{6m+2m} x time = 48m

8m x time = 48m

Time =48m /8m

Time=6 days.

Sakshi12/05/2016 at 11:46 pmIf 5 men and 6 women complete a work in 6 days,10 men and 4 women complete a work in 5 days, to how much time will 15 men and 9 women take ?

Sir can you please explain with easy steps.

devendra13/05/2016 at 1:19 am(5m+6w)*6=(10m+4w)*5

30m+36w=50m+20w

20m=16w => 5m=4w

now time taken by 15m and 9women is (5m+6w)*6 /(15m+9w)

(4w+6w)*6 /(12w+9w)

10w*6/21w

60/21=20/7days

syed kadir29/07/2021 at 9:01 pm(5m+6w)*6 = (10m+4w)*5

on solving we get,

m=(4/5)w

distance= speed * time

distance= (10m+4w)*5

we know that,

m=(4/5)w

distance= (10*4/5 +4w)*5

distance= 60w

speed*time= distance

(15m+9w)*time =distance

(15*4/5 w +9w) * time = 60w

(12w + 9w) * time = 60w

time = 60w/21w

time = 20/7 days

somia14/05/2016 at 11:49 amcan anybody please tell me, where to get the art n culture pptx ???? in mrunal.org/download there are only economy n geography pptx. besides i am also not able to find the pptx of mrunal sir’s latest articles. if anybody knows kindly help..

Thanks.

samuel29/05/2016 at 2:33 pmif five men cleared a portion of land for 4days, how many days will it take eight men to clear the same portion of land

mani25/07/2016 at 7:39 pm5men = 4 days

8men = x days

as men is directly proportional to days

5*4 = 8*x => x= 2.5 days

syed kadir29/07/2021 at 9:05 pm5m * 4 = 8m * T

20m = 8m * T

T = 20m/8m

T = 5/2 days or 2.5 days

mani25/07/2016 at 7:34 pm1 old man or 2 girls or 3 boys can complete a work in 88 days. 1 old man, 1 girl and 1 boy together will do it in

can sum1 solve dis for me?

Ashik25/12/2017 at 9:26 pm1m=2g=3b=88 days.

So, 1 men’s per day work =1/88

Similarly, 1 girl=1/176

1boy=1/264

take the LCM and add 1/88+1/176+1/264=?

6+3+2/528 ie., LCM(88,176,264)

=11/528=1/48=48 days

rajesh09/08/2016 at 6:22 pmQ- 8men can complete a piece of work in 4 days, 12 women can complete the same piece of work in 4 days, whereas 8 children can complete the same piece of work in 8 days. 2 men , 8 children , and 3 women were to finish the remaining work in 2 days, how many total women would be required?

asked in PNB PO 2009

kindly reply to this question in short

Ashik25/12/2017 at 9:44 pm8m =1/4

12w=1/4

8c=1/8

Therefore,per men,children and per women work is,

1m=1/32

1w=1/48

1c=1/64

Questions is…2m,8c,3w finishes the remaining work in 2 days.

total work =2*1/32+8*1/64+3*1/48 completes in 2 days.

i.e, 1/16+2/16+1/16=4/16=1/4th of the work in 2 days.So, 1 complete work in…

1/4=2=>1=2*4=8.

therefore total women required = 1/48*8=6 women.

Rajneesh kumar22/05/2019 at 10:07 pm12 men and 18 women can reap a field in 14 days , then 8 men and 10 women can reap the same field in.

J v Mohan reddy04/02/2020 at 12:06 pm12m+18w = 14

168m or 252w = 1 day

8m+10w

=8(1/168) + 10(1/252)

=1/21 + 1/126

=7/126

=1/18

8m +10w can reap a field in 18 days

Sunil Kumar09/09/2016 at 9:48 pm8 men and 4 women together can complete a piece od work in 6 days. The work done by a man in 1 day is double the work done by a woman in 1 day. If 8 men and 4 women started working and after 2 days 4 men left and 4 new women joined. In how much time the work will be complete?

Sunil09/09/2016 at 9:56 pm8 men and 4 women together can complete a piece of work in 6 days. The work done by a man in 1 day is double the work done by a woman in 1 day. If 8 men and 4 women started working and after 2 days 4 men left and 4 new women joined.In how much time the work will be complete?

abhinav03/06/2019 at 4:41 pm5 days after the new women joined and men left.

Bithi24/01/2020 at 9:31 pm5 day

Johnp14/10/2016 at 1:54 amIf a machine can do a piece of work in 18 hours, how long will it take 3 machines

Ashik25/12/2017 at 9:53 pm1m=18days

3m=?

m=18/3=6 days.

syed kadir29/07/2021 at 11:00 pmdistance = distance

speed * time = speed * time

1 * 18 = 3 * time

18 = 3 * time

time = 18/3

time = 6

Anitha. D17/11/2016 at 10:46 am32 men can complete a job in 70 days and 40 women in 72 days. 20 men started working and after 1/4th work was completed they were replaced by 48 women. In how many days was the whole work completed?

rajashekhar22/03/2018 at 11:00 pm73 days

abhay03/01/2017 at 12:58 amSir i need answer …one question in maths it irritats me a lot would u please give answer to me

Jitesh02/07/2017 at 11:35 am3men and 4women can do a piece of work in 10days. 2men and 5 women can do same piece of work in 12days.

Find how much days it require to do the same piece of work by women only.

rohit22/07/2017 at 1:29 amsimple question but please answer

8 men and 8 women can complete a job in 10 days. in how many days 10 women alone can complete it ?

Dilpreet02/09/2017 at 9:29 pm1 man or 1 woman or 1 child can do a piece of work in 69 days. Then in

How many days will 1 man 1 woman and 1 child will complete?

shashikant sharma18/09/2017 at 10:53 pm23 days .complet hoga..mai ….dilpreet……

pavan24/07/2018 at 8:59 pm23 days

Akshay Dongre22/11/2017 at 7:31 pmRohan and sohan working on an assignment .rohan take 6 hour to type 32 pages and sohan take 5 hour to type 40 pages.how much time will they take,working together on two diffrent computers to type an assignment of 110 pages

Rohan Sharma14/08/2019 at 12:23 pm8.25 hours is the answer

Speed of Rohan, R= 32/6

Speed of Sohan, S =40/5

Now, total time taken by both of them for completing 110 pages will be, let x

so, new equation will be

R*x+S*x=110

x(R+S)=110

x(32/6 + 40/5)=110

x(16/3 + 8)=110

x((16+24)/3)=110

x=110*3/40

x=33/4 = 8.25

priyanka02/01/2018 at 7:05 amI have a question if 10men and 15women can complete the work in 6days.in how many days one women do the job

adi25/11/2018 at 1:16 pmincomplete question

pratik kumar mantri17/08/2018 at 1:07 pm7 men and 16 women do a work in 15 days then how many days need by 5 men and 8 women to complete the same work .

plz any one answer with proper methood plzz

Rohan Sharma14/08/2019 at 12:24 pmCannot be determined as the question has 2 variables and one equation

Shruthi01/10/2018 at 4:00 pm2 male,6 female,and 8 girls can do a work in 192 hrs,4 male and 16 girls can do it in 160 hrs,4 male and 6 female can do it in 240 hrs .10 male and 24 girls can do it in.

Samarendra tarai22/02/2019 at 12:39 pmAns…pls…15men,18women&24boys can do a work in 15 days.then how many days 18men,27women&36boys can do this work? Pls…..ans….

Lahu Rathod31/07/2021 at 8:52 pmSir pdf