In a marriage hall 120 marriages were held in a particular year. The age distribution is as shown below Determine the maximum age among youngest 30% of brides.
Age  No. of Brides 
1820  12 
2022  30 
2223  30 
2324  22 
2426  18 
2628  8 
Concept/Principle
Original question: Determine the maximum age among youngest 30% of brides.
Let me rephrase the question.
 In hall, 120 brides are standing in ascending order of their age (20..23…25 and so on)
 The first 30% brides =120 x 0.3=36 brides.
 The age of these 36 brides, is less than “m” years. Find “m”
The situation calls for a cumulative frequency (CF) graph.
Make a new column
Age  No. of Brides  c.f. (less than) 
1820  12  0+12=12 
2022  30  12+30=42 
2223  30  42+30=72 
2324  22  72+22=94 
2426  18  94+18=112 
2628  8  112+8=120 
This is cumulative frequency “less than” graph.
Observive first cell of “CF”, it has number 12
It means 12 girls have age less than 20 years.
Similarly 42 girls have age less than 22 years and so on.
Now make a cumulative frequency graph, with Age in years on Xaxis and C.F. on Yaxis
Basically we’ve to plot these following numbers:
Age less than (X axis)  No of brides (Y axis) 
20  12 
22  42 
23  72 
24  94 
26  112 
28  120 
Now the biggest problem: (stupid) scales.
A typical graph paper has drawable area of 25 x 19 cm.
We want the graph to be evenly ‘spread’ across the paper, we don’t want a very small graph else we cannot find exact answer.
Scale on Xaxis
 X axis= minimum observation is 20 and max is 28. So we’ve to plot 2820=8 years.
 If we take 1cm=1 year, then entire data can be plotted in 8 cm.
 but then graph will look too small and narrow.
 So let’s increase the scale. Instead of 1 cm=1 year, let’s take 2 cm=1 year.
 In that case, to plot 8 years, we’d need 16 cm.
 Our graph paper can easily accommodate this, because we have 25x19cm paper.
 Therefore, scale on x axis: 2cm =1 year (or 1cm=0.5 year).
Scale on Yaxis
 Difference between maximum and minimum observation: 12012=108 brides.
 How about 1 cm =5 brides?
 To plot approx 110 brides, we’d need 110/5=22 cm. Again Our graph paper can easily accommodate this because we’ve 25×19 cm paper.
 So we take scale on Y axis: 1 cm=5 Brides.
 Now plot those numbers. It’ll look something like this image:
Finding 30% brides
The question says “maximum age among youngest 30% of brides”
Total brides=120, and in the graph paper, we’ve plotted them in ascending order (age is going on like 20….22…23…)
30% of total brides
=120 x 0.3
=36 brides
On the Yaxis, locate number 36 then draw a parpendicular line from that number to the cumulative frequency graph. (Pink colored line going towards right side.)
It will cut the cumulative frequency line somewhere.
From that point, draw anohter parpendicular line towards Xaxis (blue line going downwards).
The point at which it cuts Xaxis= our answer.
In above graph, it cuts at 21.75 years.
Therefore answer: maximum age among youngest 30% of brides is 21.75 years.
Practice questions
In a marriage hall 120 marriages were held in a particular year. The age distribution is as shown below:
Age  No. of Brides 
1820  12 
2022  30 
2223  30 
2324  22 
2426  18 
2628  8 
Find following
Question  Concept Explained in this youtube video 
Find Average age of brides  http://www.youtube.com/watch?v=FC8CQGY1CUE&feature=plcp 
Find median Age of brides using

http://www.youtube.com/watch?v=uaHBu2kz8pM&feature=plcp 
Find modal age of brides  http://www.youtube.com/watch?v=BUdd3PBe6Q&feature=plcp 
Find Standard Deviation of the data.  http://www.youtube.com/watch?v=boHDPTX5YnU&feature=plcp 
Basically this is a “Continuous Data Series”. So, use this readyreference Statistics formula table to solve above questions accordingly:
Thank you for such thankless job
LOLZ!!! What do you mean???
shouldn’t the answer be 21.6? (by formula…)
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The committee was constituted under the chairmanship of Prof Arun S Nigavekar, former chairman, University Grants Commission (UGC). “Till now, no decision has been taken by the government on these recommendations,” the Minister said.
i think this might help
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Is it correct to solve this question like this
1st– 30%of120=36
2nd– age 18,19,20– no.=12+15=27
3rd– rest 3627=9 in between 20 and 21 ie.9/15=0.6
hence answer is 20.6
i think the answer should be 21.6